Manually adding subscribers
complete
Andrija Krstic
complete
Given that this is already possible by going through the checkout as a customer or by resubscribing by logging in as an existing customer, we consider this complete and possible :)
Stefan Pretty
under review
Stefan Pretty
So this is now possible for existing customers by logging in as them from the admin. Is the goal of this to add them including their card details etc, manually?
Andrija Krstic
Stefan Pretty: Yes, this is not for re-adding existing customers, but entirely new customers. Now when I think of it, it's basically as going through the checkout for the new customers...
Stefan Pretty
Andrija Krstic: yep that is possible by going through checkout as them 🙂
Anne Hart
Andrija Krstic: I think it would be beneficial for when businesses host giveaways as well. I have someone who will be winning a year long subscription soon and it would be nice to bypass charging them for this reason.
Andrija Krstic
Anne Hart: In this case you can create 100% coupon and apply it to the customer's subscription as well ;) He'll apply the coupon on the checkout
Anne Hart
Andrija Krstic: Workarounds are great temporarily or on a one time use basis but they really tend to mess up any true analytics that one does. There seem to be a lot of workarounds.
Andrija Krstic
Anne Hart: How do you expect this particular case to mess analytics? This is not a workaround as well I provided, I was talking more of a solution for giveaways. Applying 100% coupon to someone's account is how other merchant's do it as well.
Mobile Roadside
Great idea
Kevin Rivenburgh
yeah i have a lot of family members that would like to just fill out a check, it would be nice to be able to add them to the workflow manually.
Andrija Krstic
Kevin Rivenburgh: Thanks for the feedback. Yes, I added this on the request of some customers I was on the phone with. We are currently rehauling the checkout process and we are working on implementing this functionality on Subbly. :)
Randi Hewit
This would be helpful to us too.